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Ozone converting calculation.


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#1

janhastevens

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Geplaatst op 13 juni 2008 - 10:07

How can I convert gram/ltr ozone to ppm ozone in the air.

To be concrete: If I have a booth or box containing 200 ltr. of ambient air under standard pressure and a temperature of appr. 25 degrees Celsius and if the ozone generator in the booth produces 250 mgr ozone per ltr., how many PPM ozone do I have in the booth?

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#2

SamtheChemist_CF

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Geplaatst op 13 juni 2008 - 10:33

Mhh I'll talk back in english but most of the people her speak dutch....

PPM stands for Parts Per Million so if you have 1 PPM you have 1 part ozone per milion parts of Oxygen.

With the data you have provided you can calculated the amount of PPM by yourselve in my opinion.

Hope you got the help you wanted...

#3

SamtheChemist_CF

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Geplaatst op 13 juni 2008 - 10:36

p.s. if you had looked @ for instance wikipedia you would have found this:
PPM - Wikipedia

#4

DeeVee

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Geplaatst op 13 juni 2008 - 11:39

You say you have 200l of ambient air. Then you have approx. 40l of O2. The convertion of O2 into O3 goes according following reaction

3O2 --> 2O3

So you need 3 mole oxygen to produce 2 mole of ozone. If you know that, under standard conditions, you have 22.4l per mole, then you can calculate how much ozone you can produce

#5

epiphonix

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Geplaatst op 13 juni 2008 - 11:49

gram/ltr

200 ltr.

250 mgr ozone per ltr.

Mogen we niet gewoon in het Nederlands verder gaan? (Jan Stevens kŠn angelsaksisch zijn, maar ik gok toch op een Vlaming/Nederlander)

Dus tot er duidelijkheid is
-even wat muggezifterij:
Gram = g
dus milligram = mg

Liter = L

En de rest zijn iets tť populaire eenheden naar mijn mening.


-some hair-splitting:
Gram (B.E.: Gramme) = g
so milligram = mg

Litre (or liter) = L

The other units are a little too popular, I think.


25 degrees Celsius

Better: 25 centigrades (Although both units are used)

Veranderd door epiphonix, 13 juni 2008 - 11:50


#6

janhastevens

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Geplaatst op 14 juni 2008 - 11:10

The question is not how much ozone the generator can produce.
It is given that the generator produces 250mg/l ozone.

If that generator is situated in the booth and the booth is filled with 200 l of normal ambient air what is the ozone concentration in the booth depicted in PPM after passing by some time.

#7

janhastevens

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Geplaatst op 14 juni 2008 - 11:16

I checked wikipedia but didn't found anything that could help me further.
So for the time being I rely on you chemists.

#8

Fuzzwood

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Geplaatst op 14 juni 2008 - 13:01

Very simple actually. The thing produces 250 mg/l in a room of 200 l. This means that in 1000 l, there will be 1250 mg ozone present, or 1250 mg/kl. This is 1250 ppm.

Veranderd door FsWd, 14 juni 2008 - 13:02


#9

DeeVee

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Geplaatst op 14 juni 2008 - 16:45

[STKM]
I think it's tricky!

Ozone is very unstable. Thus, after some time, there will be NO ozone anymore :)

#10

janhastevens

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Geplaatst op 16 juni 2008 - 08:26

I'm in doubt this is the right solution. It is a very small ozone generator and, however it continiously produces ozone in the booth, a concentration of 1250 ppm looks much too high. I more expect a concentration of less than 10 or 15 ppm.
What means mg/kl?

#11

*_gast_Gerard_*

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Geplaatst op 16 juni 2008 - 09:31

The generator produces 250 mgr ozone per ltr, i'm missing the time it needs to produce 1 l.
Ozone is not very stable therefore if the output from the generator is low there wil be a Equilibrium Ozone produced/Ozone desintegrated.
This Equilibrium can't be calculated so its impossible to calculate the concentration ozone in the booth

#12

ArcherBarry

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Geplaatst op 16 juni 2008 - 09:42

mg/kl = miligrams per kilo liter = 1,0*10-3gram per m3 air or in other words, parts per million

Niet geschoten is altijd mis, en te snel schieten vaak ook.

 

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#13

janhastevens

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Geplaatst op 16 juni 2008 - 11:13

Thanks a lot folks, Gerard is right I think.
We can close this thread.

#14

Fuzzwood

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Geplaatst op 16 juni 2008 - 12:50

Might still be a nice study if you have the time for it :P

#15

janhastevens

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Geplaatst op 17 juni 2008 - 09:47

I'm doing research in a project to create a test cabin for the desinfestation of wounds caused bij burns.
As you can imagine it is very difficult and painful to treat that kind of injuries.

The idea is to do that with an application of dry ozone consisting air warmed up to 37OC on the wounded area.

The ozone concentration has to be high enough to completely hygienise the wound within appr. 5 to 10 minutes.

Although the precise concentration of ozone in the booth is not that important I need to know how to manage the proces.

After the treatment the ozone concentration is to cut down with an active carbon filter.





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